Find the x & y intercepts f(x)=x²-9x+7 please help me
\[f(0)=0^2-9\times0+7=7\] which is the y intercept.\[f(x)=0=x^2-9x+7=>x=(9\pm \sqrt{53})/2\]Which are the x intercepts.
the answer is x-intercept is (8.1,0.9) y-intercept is (0,7) how did they get these answers
The x intercepts occur when y=0 (or, if you like, f(x)=0) so you just put this into you equation (remember, this is a quadratic function this will have two solutions and the function will therefore have two x intercepts). Similarly, the y intercept occurs when x=0, so you put this into your equation.
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i know how to do y-intercepts but not x
X intercepts occur when f(x)=0, so make your equation equal to zero and solve.
plz show me how
Do you know how to solve a quadratic equation?
no
i just found a great website that did it for me ty
Good :)
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