Question

determine the equation of the tangent to y=lnx at x=e

Answer 1

y'=1/x
y' (at x=e) =1/e
y=mx+b is a line
y=1/e*x+b
we know a point on this line (if x=e, then y=ln(e)=1)
1=1/e*e+b
1=1+b
b=0
so y=1/e*x

Answer 2

coool thankss