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[2x-1]/[(x+2)(x^2+3)]=0 solve the equation.
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x=1/2
how did you get it?
hold on let me type it out
ok
hold on im going to type it out on word then ill attach it, its just easier
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alright
the bottom doesn't make a fraction 0 only the top does so set 2x-1=0 and solve for x 2x=1 x=1/2 but you also have to be careful that this doesn't make the bottom zero since 0/0 does not exsit but you are good the answer is 1/2
oh ok but how come you dont do anything to the bottom?
I have a much longer description lol click on the file i have attached
the only thing that makes a fraction zero is the top
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oh ok it makes sense thanks guys :)
do either of yall no how to do this one? x^3-2x^2-5x+6=0
x=1,3,-2
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