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what is the x-intercept of the tangent to y=e^x at x=45
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line tangent to the graph has slope \[e^{45}\]
and goes through the point \[(45,e^{45})\] so equation is \[y-e^{45}=e^{45}(x-45)\]
x intercept means set y = 0 and solve \[0-e^{45}=e^{45}(x-45)\] \[-1=x-45 \] \[x=44\]
check my algebra because i am tired
i got x=44 as well
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thank you, because of yur help i just might graudaute
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