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Mathematics 21 Online
OpenStudy (anonymous):

who is good at word problems!

OpenStudy (anonymous):

ok... the rectangle has a perimeter of 126 . its length is 5 more than its width, find the dimensions

OpenStudy (anonymous):

P=(L+W)*2 L=5*W 126=(5W+W)*2 126=6W*2 126=12W w =126/12 W = 10.5 L=10.5*5 L=52.5 check (52.5+10.5)*2 63 *2=126

OpenStudy (anonymous):

If I deserve medal then give me one

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