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Mathematics 15 Online
OpenStudy (anonymous):

what's the derivative of sin2x?

OpenStudy (anonymous):

\[2cos(2x)\]

OpenStudy (anonymous):

2cosx

OpenStudy (anonymous):

not 2cos(x)

OpenStudy (anonymous):

2cos(2x) via the chain rule

OpenStudy (anonymous):

yeah i'm sorry, i forgot. 2cos2x

OpenStudy (anonymous):

thanks satellite73

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