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Given the following functions f(x)=x^2-3x+4 and g(x)=x-2 fine (f0g) (x)
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kizzy please take a look at your previous post
\[f(g(x))=f(x-2)=(x-2)^2-3(x-2)+4\]
hey satellite i need your help
then some algebra \[(x-2)^2-3(x-2)+4=x^2-4x+4-3x+6+4\] \[=x^2-7x+14\]
what do you need hikari?
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