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solve for x: log (7-x) - log (3x+2)=1. please help, have to take precal exam in the morning
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subtraction=division
that doesnt give me enough info bro haha im sloww. can you tell me the answer so i can go through and work out the problem?
The answer, if I knew it, would help you less. log equations require steps. the left hand side can be grouped in to one term log a - log b= log (a/b)
\[log((7-x)/(3x+2))=1\] \[log((7-x)/(3x+2))= log10\] \[(7-x)/(3x+2)= 10\] \[x= -13/31\]
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