Question

At which values of x does the function F(x) have a vertical asymptote?1/7(x+2)(x+3)

Answer 1

Set denominator to zero, solve for x

Answer 2

idk how to do that:(

Answer 3

Here is an example 1/(x+1)
take denominator x+1=0
x=-1
Asymptote at x=-1

Answer 4

Denominator: 7 . (x+2) . (x+3)
-> x+2 = 0 -> x = -2
-> x+3 = 0 -> x = -3
At these two points the function have vertical asymptote.

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