Question

solve for x:
log(x+4)-log(x+3)=2

Answer 1

log(x+4)=log(x)+log4
log(x+3)=log(x)+log3

so

= log(x)+log(4) + log(x)+log(3)
=2log(x)+(log(4)+log(3))
2log(x)=-log(4)-log(3)
log(x)=(-log(4)-log(3))/2
x=10 ^-(log(4)-log(3))/2

Answer 2

\[x=10^{-(\log4+\log3)/2}\]

Answer 3

that is what I got