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If the equation y = 6(1.6)^x is plotted on a semilog scale graph, then the linearized equation will be log(y) = m x + b where m = ? b = ?
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m=1.6, b=log6
log base 6? or log(6)?:)
log(6)
thanks!:D can u show steps please:D! i can prob figure it out later though
y = 6(1.6)^x this is what u have taking log to both sides log y=log6+log(1.6)^x =log 6 +x log 1.6
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