Question

find the area and perimeter of a square with a diagonal of 10 inches

please help :) thanks

Answer 1

\[x^{2}+x ^{2}=10^{2}\]\[2x^{2}=100\]\[x^{2}=\frac{100}{2}\]\[x=\sqrt{50}\]\[A=\sqrt{50}\times \sqrt{50} \]
A=50
\[P=4\sqrt{50}\]
P=28.3

Answer 2

the measure of its side is \[5\sqrt{2}\]
so, we are going to use the formula in finding its perimeter which is A=4s
=4(5\[4(5\sqrt{2}\])

its perimeter is \[20\sqrt{2}\] inches

\[A=s ^{2}\]
\[A=(5\sqrt{2})^{2}\]
\[A=25(2)\]
A=50 in^2