Question

√(9x+67) =x+5 solve

Answer 1

square both sides.
\[9x+67=(x+5)^2\]
\[9x+67=x^2+10x+25\]

Answer 2

\[x^2+x-42=0\]
now factor \[(x+7)(x-6)=0\] so we get \[x=-7\] or \[x=6\] and now we have to check the answers because we squared.

Answer 3

\[\sqrt{9\times 6+67}=6+5\]
\[\sqrt{54+67}=11\]
\[\sqrt{121}=11\] checks

Answer 4

-7 doesn't work because the left hand side
\[-7+5=-2\] is negative and the square root of anything is positive

Answer 5

so the answer is x=6?