Question

Find the solution to each system by the substitution method.
10x+3y=-8
2x+y=2

Answer 1

second equation gives \[y=2-2x\] substitute in the first equation to get
\[10x+3(2-2x)=-8\]

Answer 2

10x=6x+6=-8

Answer 3

\[10x+6-6x=-8\]
\[4x+6=-8\]
\[4x=-8-6=-14\]
\[x=-\frac{14}{4}=-\frac{7}{2}\]

Answer 4

Ok

Answer 5

now you have to substitute back to find y

Answer 6

\[y=2-2x\]
\[y=2-2\times- \frac{7}{2}\]
\[y=2+7\]
\[y=9\]

Answer 7

hold on let me check

Answer 8

I was doing while you were teaching me and i got the smae thing useless i'm wrong too. I am understanding this

Answer 9

oh yeah it is right!