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Find the solution to each system by the substitution method. 10x+3y=-8 2x+y=2
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second equation gives \[y=2-2x\] substitute in the first equation to get \[10x+3(2-2x)=-8\]
10x=6x+6=-8
\[10x+6-6x=-8\] \[4x+6=-8\] \[4x=-8-6=-14\] \[x=-\frac{14}{4}=-\frac{7}{2}\]
Ok
now you have to substitute back to find y
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\[y=2-2x\] \[y=2-2\times- \frac{7}{2}\] \[y=2+7\] \[y=9\]
hold on let me check
I was doing while you were teaching me and i got the smae thing useless i'm wrong too. I am understanding this
oh yeah it is right!
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