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how do I solve to find the solution -14< or equal to 3x -7< or equal to -2
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\[-14\le 3x-7 \le-2 \implies -7\le3x \le5 \implies -{7 \over3} \le x \le {5 \over 3}\]
AnwarA you are a fast typer XD
You can use interval notation and write \(x \in [ -\frac{7}{3}, \frac{5}{3}]\).
@behee: sorry for that :D
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-14 </ 3x -7 </ -2 ; +7 -7 </ 3x </ 5 ; /3 -7/3 </ x </ 5/3 ; Anwar was right yay!!
thank you
can you explain why is it in fraction anwarA
Because I divide both sides by 3.
All sides*
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thank you anwarA
You're welcome. It's just Anwar :D
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