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Solve: w^2-7w-8=0 it ask what the solution is for w
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(w-8)(w+1)=0 w=8 w=-1
Does it matter how it is written (-1,8) or (8,-1)
(-b(+-)sqrt(b^2-4ac))/2a. a=w^2 = 1 b=-7w = -7 c=-8 w= (7+-sqrt(49-4*(1*-8)))/2 = (7+-sqrt(81))/2 = (7+-9)/2 = 16/2 and -2/2 => w=8 V w=-1 It doesn't matter which order you write the answers.
V means "and" in mathematical notation. Just wanted to avoid any confusion.
oh ok
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