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Mathematics 17 Online
OpenStudy (anonymous):

help Please!

OpenStudy (anonymous):

first one \[3^x\] is alway increasing so smallest value will be from the smallest x

OpenStudy (anonymous):

\[-\frac{3}{4}\]

OpenStudy (anonymous):

second one \[4^{x+2}=4^x\times 4^2=4^x\times 16\]

OpenStudy (anonymous):

so you get \[16\times4^x=48\] \[4^x=\frac{48}{16}=3\]

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