Question

\[f(x)=4(x-2)^{2}-1\]

vertex?

Answer 1

Have you tried graphing? :)

Answer 2

(2, -1)

Answer 3

(2,-1)

Answer 4

nope not yet

Answer 5

it is displayed for you.

Answer 6

you don't have to graph this to find the vertex
it is (2,-1)

Answer 7

\[f(x)=a(x-h)^2+k\] has vertex (h,k)

Answer 8

i was just fixing to say that :(

Answer 9

what would the x-intercept of parabola for this would be??

Answer 10

set y=0 and solve for x

Answer 11

????