Question

6*2^2x - 13*6^x + 6*3^2x = 0
what is the value of X ?

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

you sure you typed that right?

Answer 3

lets see if we can factor 6u^2-13uv+6v^2=0

Answer 4

I get x=1

Answer 5

how

Answer 6

see if this helpful to you k?

Answer 7

so what's your answer ?

Answer 8

3u-2v=0 implies we have 3u=2v
2u-3v=0 implies we have 2u=3v
remember u=2^x and v=3^x
so we have
\[3*2^x=2*3^x \]
and
\[2*2^x=3*3^x\]

Answer 9

get your x on one side
3/2=3^x/2^x
3/2=(3/2)^x
so x=1 for the first equation

Answer 10

2/3=3^x/2^x
2/3=(3/2)^x
x=-1 for the second

Answer 11

thanks

Answer 12

but

Answer 13

i will leave the checking part to you

Answer 14

how you 13uv is = -4uv-9uv

Answer 15

i was trying to factor
to factor you look for factors of a*c that add up to be b
6(6)=36
(-4)(-9)=36
-4-9=-13

Answer 16

ok