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OpenStudy (anonymous):
The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 108 cm^2.
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OpenStudy (anonymous):
L=2W-6 108= W* (2W-6) 108 =2W^2 -6W 0 = (2W^2 -6W -108)2 0 = W^2-3W-54 (W+6)(W-9)= 0 W=-6 W=9 is solution L=(2*9)-6 L= 12
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