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\[f(x)=3(x-1)^{2}-2\] vertex? x-intercept? y-intercept?
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vertex (1,-2)
x intercepts, set y to 0
(x-1)^2 = 2/3 x-1= +- sqrt (2/3) x= 1 +-sqrt(2/3)
y intercepts, let x be zero so y= 3(-1)^2 -2 = 3-2 =1
The x-intercept has to be a decimal
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