Question

If a pro basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang-time function V=48t^2

Answer 1

20=48t^2
5/12 = t^2
sqrt(5/12) = t

Answer 2

So what is the exact hang time of the basketball player in seconds?

Answer 3

sqrt(5/12)

Answer 4

\[\sqrt{\frac{5}{12}} = \frac{\sqrt{5}}{2\sqrt{3}} = \frac{\sqrt{15}}{6}\]

Answer 5

Thank you