Question

Verify the following identity: (1-cos2θ)/(sin2θ) = tanθ

Answer 1

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Answer 2

sin2x = 2sinxcosx
cos2x = cos^2 - sin^2

1-cos2x = sin^2 +(1-cos^2) = 2sin^2
sin2x = 2sinxcosx

\[\frac{2\sin ^{2}x}{2\sin x \cos x} = \frac{\sin x}{\cos x}=\tan x\]