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in triangle DEF, m
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DE=6 cosF=8/10 ---->maybe abt 30..
arccos(8/10)=36.9
okay thats the right anser, but how do i show my work?
Pythagoras theorem 10^2=8^2+DE^2 100=64+DE^2 DE=sqr36=6 cosF=8/10
understand it?
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yessm thank you so much
uw :)
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