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Mathematics 6 Online
OpenStudy (anonymous):

16x^2+2x-3=0

OpenStudy (anonymous):

factor as \[(2x+1)(8x-3)=0\]

OpenStudy (anonymous):

get \[2x+1=0\] \[x=-\frac{1}{2}\]

OpenStudy (anonymous):

or \[8x-3=0\] \[x=\frac{3}{8}\]

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