Question

can someone please show me how tofind the integral of x^3sinx^2dx

Answer 1

u use the integration by parts formula

INT (u dv) = uv - INT vdu

Answer 2

yah i know that but im actually having trouble setting it up

Answer 3

ok - u want to make INTvdu easy to do if possible

try u = x^3 and dv = sin^2x and if this is problem reverse them

Answer 4

for some reason people first u substitution bu i do no know why

Answer 5

there is a recomendation in the literature but i cant remember it - I just dive in and see what happens!