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please help......... solve for x x^3+2x^2=13x+6
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solve for x ...... hmm...
get it all to one side to keep track of it
x^3+2x^2=13x+6 x^3 +2x^2 -13x -6 = 0
trial and error is my best shot for this; we can narrow down the pool by using the ......something something thrm lol
+- 1,6,2,3 and synthetic them to test for 0 remainders
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x=6 ? 6| 1 +2 -13 -6 0 6 48 .....aint gonna be it ---------------- 1 8 35
ok thanks i got it from there
x=3? 3| 1 +2 -13 -6 0 3 15 6 -------------- 1 5 2 0 <-- yay!!
now we got a quad left
(x-3)(x^2 +5x +2)
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yea thanks :)
youre welcome :)
i knew you could do it; I just didnt know if I could ;)
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