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OpenStudy (anonymous):
In right triangle ABC, C is the right angle. BC=5 and AB=13. What is the value of sec A?
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OpenStudy (dumbcow):
secA = 1/cosA = hypotenuse/adjacent = 13/12
OpenStudy (nice):
12 came from Pythagoras : (AC)^2 + (BC)^2 = (AB)^2
OpenStudy (anonymous):
Yay! Thanks(:
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