Question

Anyone please help w/ steps to simplify ᵌ√729x^4y^5 (everythng is under the radical)

Answer 1

break it into parts
\[\sqrt[3]{729}=9\]
\[\sqrt[3]{x^{4}} = \sqrt[3]{x ^{3}x ^{1}} = x \sqrt[3]{x}\]
\[\sqrt[3]{y^{5}}=\sqrt[3]{y^{3}y^{2}}=y \sqrt[3]{y^{2}}\]

Answer 2

9xy ᵌ√xy^2

Answer 3

thank you so much