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x-1/3=3 solve
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x = 3 +1/3
x=3+1/3; =(9+1)/3 =10/3 =3.33
x - 1 ------- = 3 3 x - 1 = 9 {multiplied both sides by 3} x = 10 {added 1 to both sides}
if you multipliy both sides by 3 you must multiply EVERYTHING by 3 and get \[3x-1=9\]
not \[x-1=9\]
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so is my solution correct?
Yeah it's if the problem was \( \frac{x-1}{3}=3\).
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