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An investment of 125000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest, the second 6%, and the third 9% Total interest from the investments was 9090 The interest from the first investment was 2 times the interest from the second. Find the amounts of the three parts of the investment.
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f(.08) +s(.06)+t(.09) ..... yada yada
A+B+C = 125000 .08A + .06B + .09C = 9090 .08A = (2)(.06B)
f(.08) = 2s(.06)....yeah like that
thanks u two
A = 72,000 B= 48,000 C = 5,000
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first investment = 72,000 ; second investment = 48,000 ; third investment = 5000
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