The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle.

please show all work!

Question

The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle.

please show all work!

anonymous · Answer

the angles are x, 3x, (x+3x+10)=4x+10.  The sum must be 180

x+3x+4x+10=180
8x=170
x=85/4

The third angle was 4x+10

4(85/4)+10=95

anonymous · Answer

Let the three angles be <1, <2, <3. We know that the sum of angles of a triangle should be 180. So eqn.1 is <1 + <2 + <3  = 180 -----(1)
<2=3*<1----(2)
<3=10+<1+<2 ------(3)
Now solve the equations (1),(2),(3)