Trains A and B are traveling in the same direction on parallel tracks. Train A passes a station at 2:10pm. If train B passes the same station at 2:25pm, what time will train B catch up to train A?

Question

Trains A and B are traveling in the same direction on parallel tracks.  Train A passes a station at 2:10pm.  If train B passes the same station at 2:25pm, what time will train B catch up to train A?

watchmath · Answer

You forgot to put information about the speed of the two trains.

anonymous · Answer

oops, train a is traveling at 100 mpr and train B at 120 mph.

watchmath · Answer

Let $x$ be the time needed for the traind B to catch up the train A after 2:25 Pm.
As train B leaving the station, train A already left the station for 15 minutes =1/4 hour. It means train A is already 1/4*(100)=25 miles from the station.

Now the two distance after x hour :
distance A = 25 + 100x
distance B = 120x

the two distance are equal when train B catch up with train A
25+100x=120x
25=20x
x=25/20
x=1.25 hour = 1 hour 15 minutes
So train B catch up train A at 2:25 + 1 hour 15 minutes = 3:50 pm

watchmath · Answer

Sorry it should be 3:40 pm

anonymous · Answer

Thank you!