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Find the vertex of f(X)= 3x^-gx+8
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i guess u mean x^2-gx+8?
x= -b/2a = g/6 y= 3(g/6)^2 -g(g/6) +8 y = g^2/12 -g^2/6 +8 y = -g^2/12 +8 vertex: (g/6, -g^2/12 +8)
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