Question

Find an equation of the line passing through the point (6,5) and perpendicular to the line whose equation is 2y+3x=6.

Answer 1

Given equation is 2y+3x=6
= 2y=6-3x
=y= 3-3/2x
now we have equation of line in a form of y=mx+c
slope m=-3/2
prependicular slope=2/3
now equation of line is given by y=mx+b
given points are (6,5)
plug values
we will get
5=2/3(6)+b
5=4+b
b=1
now equation of line prependicular to given line is y=2/3x+1

Answer 2

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