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How to solve an equation using factoring and quadratic formula ? x^+15x-54=0?
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X^2+18x-3x-54=0 x(x+18)-3(x+18)=0 x=3, -18
For factorizing, Find two numbers whose product is -54 and sum is 15 18 & -3 \[x^2+18x-3x-54=0\] \[x(x+18)-3(x+18)=0\] \[(x+18)(x-3)=0\] x={-18,3}
thanks
For quadratic formula, ax^2+bx+c=0 \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] So it would be \[\frac{-15 \pm \sqrt{225+ 216}}{2}\] =6,-18
okay thank you
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same equation, different roots..how come? its 3 and -18
Uh sorry, typo, its 3,-18
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