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how to solve an equation using factoring and quadratic formula ??? 2x^ - 8x = 0 ???
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2x(x-4) x=0 x=4
okay
quadratic formula \[x = (-b + - \sqrt{b ^{2}-4ac)})/2a\]
Using the formula. x= (\[-b \pm \sqrt{b) ^{2}-4ac}\])/2a a = 2 b= -8 c =0 . Plug in and Solve
It factors easily enough.
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okay
thanks
Both methods should result in identical solutions.
oh okay
That is a good check! Good luck.
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okay thank you
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