Question

Solve the equation algebraically:

Answer 1

\[e ^{2x}-5e^x+6=0\]

Answer 2

Firstly, assign \[e^x\] a variable -- let's just say x, and then plug in that variable. From there, factor the quadratic equation.

Answer 3

\[(e^x-3)(x^x-2)=0\]
\[e^x=3\[
\[x=ln(3)\]
or \[e^x=2\]
\[x=ln(2)\]

Answer 4

I'm lost now.

Answer 5

Wait... I got it. Thanks (: