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solve : 2x over 3 - 4 over x= 5 over 3
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\[\frac{2x}{3} - \frac{4}{x} = \frac{5}{3}\] is this what the problem looks like?
yes
the answer is x=4 and -1.5
how do you solve it?
\[\frac{2x(x)}{3(x)}-\frac{4(3)}{x(3)}=\frac{5}{3}\] \[\frac{2x ^{2}-12}{3x}=\frac{5}{3}\] multiply both sides by 3 \[\frac{2x ^{2}-12}{x}=5\] multiply both sides by x\[2x ^{2}-12=5x\] \[2x ^{2}-5x-12=0\] solve using the quadratic formula
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thank you :)
you're welcome
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