How can I finish this problem? m<JLN = 1/2 (m arc JN - m arc KM) m<JLN = 1/2 (x^2 + 8x - 20) 4x = 1/2 (x^2+8x-20) x^2 / x = -20 / x

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OpenStudy (anonymous):

How can I finish this problem? m 15 years ago

OpenStudy (anonymous):

unless we cross multiply the equation, so that it it becomes an equation where i have to find the √ of -20...

15 years ago

OpenStudy (anonymous):

15 years ago

OpenStudy (mathteacher1729):

\[4x = 1/2 (x^2+8x-20)\] now distribute the 1/2.. \[4x = 1/2 x^2+4x-10\] now subtract 4x from both sides \[0 = 1/2 x^2-10\] now add 10 to both sides \[10 = 1/2x^2\] See what happened there? :) You should be able to fix it from here.

15 years ago

OpenStudy (anonymous):

Thank You Thank You Thank You!!!! You are a life saver!

15 years ago

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