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express tanx secx in terms of cosx and please show steps
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tan is opposite/adjacent and sin is opposite/hypotenuse and cos is adjacent/hypotenuse i remember it like this : SOH CAH TOA
is this for a trig class?
yea
sinx/cosx*1/cosx
tan x = sinx/cosx
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tan x = sinx/cosx
still not sure how to express this answer in terms of sinx
do you have a value for x?
no i am to express the first function in terms of the second tanx secx; sinx
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