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Mathematics 13 Online
OpenStudy (anonymous):

express tanx secx in terms of cosx and please show steps

OpenStudy (anonymous):

tan is opposite/adjacent and sin is opposite/hypotenuse and cos is adjacent/hypotenuse i remember it like this : SOH CAH TOA

OpenStudy (anonymous):

is this for a trig class?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

sinx/cosx*1/cosx

OpenStudy (anonymous):

tan x = sinx/cosx

OpenStudy (anonymous):

tan x = sinx/cosx

OpenStudy (anonymous):

still not sure how to express this answer in terms of sinx

OpenStudy (anonymous):

do you have a value for x?

OpenStudy (anonymous):

no i am to express the first function in terms of the second tanx secx; sinx

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