How many ounces of a 22% alcohol solution must be mixed with 23 ounces of a 5% alcohol solution to produce a 10% alcohol solution? Round to the nearest tenth of an ounce. Can anybody explain how to do this or the other question I've posted?

Question

How many ounces of a 22% alcohol solution must be mixed with 23 ounces of a 5% alcohol solution to produce a 10% alcohol solution? Round to the nearest tenth of an ounce.  Can anybody explain how to do this or the other question I've posted?

anonymous · Answer

yes i think i can.  you add x ounces it will have .22x ounces of alcohol .  the 23 once solution contains .05*23 = 1.15 onces of alcohol.  when you add x ounces your total will be 23 + x and you want that to be ten percent alcohol, which will be .10(23+x)

anonymous · Answer

set them equal to solve:$$.22x+1.15=.10(23+x)$$
$$.22x+1.15=2.3+.10x$$
$$.22x-.10x=2.3-1.15$$
$$.12x=1.15$$
$$x=\frac{1.15}{.12}=9.58$$ rounded