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use substitution to solve the system {2x-5y=-5, -2x+8y=-58
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id rather just use common sense
3y = 63; y = 21 x = 10
thanks
actually it looks like you get 3y = -63 so y = -21 yes?
\[2x-5y=-5\] \[-2x+8y=-58\] add to get \[3y=-63\] \[y=-21\] substitute back to get \[2x-5\times -21=-5\] \[2x+105=-5\] \[2x=-110\] \[x=-55\]
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lol.... did i drop a negative
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