Question

Can you check my answers? File attached (only 9 problems)

Answer 1

checking now... 37 38 right

Answer 2

38 39 are right

Answer 3

first one is wrong

Answer 4

37 is not right lol

Answer 5

41 is wrong

Answer 6

fail... 3+2 = 5

Answer 7

^for 37

Answer 8

the last question is actually very easy

Answer 9

ok sorry i multiplied for some reason :P

Answer 10

41?

Answer 11

answer to 45 is just "3"

Answer 12

nvm i know how to do 41 and how did u get 3?

Answer 13

g(x) = -2f(x-1) + 5 , this given

Answer 14

now , g(3) , just means go the function and g , and everywhere you see an x , replace it with a 3

Answer 15

ie , g(3) = -2 f(3-1) + 5 // by subbing int the above

Answer 16

g(3) = -2f(2) + 5

Answer 17

but we were told f(2) = 1

Answer 18

the answer for 45 is 3

Answer 19

g(3) = -2 +5 = 3

Answer 20

ok i see thanks! so is everything else besades 41 correct?

Answer 21

lol I was too slow elecengineer (and I'm assuming that you're in electrical engineering.. which I am too haha)

Answer 22

no, 37 is wrong

Answer 23

well ya besides that?

Answer 24

37 should be +5

Answer 25

how do you do 42?

Answer 26

confirmed 44 righttttt

Answer 27

42 is inverse just switch the y and x around lemme see

Answer 28

so you have y=x+3 make it so that it is x=y+3

Answer 29

then you'll have y=x-3 where y=h^(-1)x

Answer 30

so whats the answer?

Answer 31

x-3

Answer 32

lol

Answer 33

oh ok and is the answer to 41 7x^3+36x^2+54x+28?

Answer 34

hello?

Answer 35

37. h(2+a) = (2+a)+3
= 5+a

38. correct

39. correct

40. correct\[41.f(x+h)-f(x) = [(x+h)^{3}+1]-(x ^{3}+1)\]\[=x ^{3}+h ^{3}+3x ^{2}h+3xh ^{2}+1-x ^{3}-1\]\[=h ^{3}+3x ^{2}h+3xh ^{2}\]
\[42. h ^{-1}(x)=1/(x+3)\]
\[43. f(x)*g(x) = (x ^{3}+1)(x ^{2}-2)\]\[=x ^{5}-2x ^{3}+x ^{2}-2\]

44. correct

45. g(x) = -2f(x-1)+5
g(3) = -2f(3-1)+5
= -2f(2)+5
= -2*1+5 f(2)=1
= -2+5
= 3