Question

The product of two negative consecutive integers is 5 more than their sum. Find the integers.

Answer 1

-2 and -1

Answer 2

can you show me the formula?

Answer 3

let the numbers be -x and -x=1

Now, with the given condition
\[-x * (-x+1) = -x + (-x+1) + 5\]
\[x ^{2} - x = x - x +1 +5\]
\[x ^{2} - x = 6\]
\[x ^{2} - x - 6 = 0\]

Now calculate

Answer 4

suppose two consecutive integers are -x and (-x+1)
now according to problem
(-x)(-x+1) = (-x)+(-x+1) + 5
x^2 -x - 6= 0
so you will got two root for that
x=-3 and x= 2
So the value of -x is 3 or -2
but it is negative integer so Integers will be -2 and -1