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prove d/dx(arccosh x) = 1/sqrt(x^2-1) implicitly thanks (:
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\[y=\cos^{-1} x\]??
hyperbolic eh...shudder
Let arcosh(x) = y cosh(y) = x (d/dx)(cosh(y)) = (d/dx)(x) sinh(y) * (dy/dx) = 1 (dy/dx) = 1/sinh(y) ;;; cosh²(y) - sinh²(y) = 1, ;;; sinh(y) = sqrt(cosh²(y) - 1) = sqrt(x² - 1) Hence, if y = arcosh(x), (d/dx)(arcosh(x)) = dy/dx = 1/sqrt(x² - 1)
thanks!
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