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m angle C is about
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ditto, same as previous.
sin63/415=sinC/362 right
This is right except where you have Sin C, should be Sin A.
\[\frac{\text{Sin}[A]}{362}=\frac{\text{Sin}\left[\frac{7}{20} \pi \right]}{415} \]\[A\to \text{ArcSin}\left[\frac{362}{415} \text{Cos}\left[\frac{3 \pi }{20}\right]\right]=0.890228=51{}^{\circ}\]\[C=180-(63+51)= 66{}^{\circ} \]
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