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((x^2+5x+6)/3x )divided by (x+3)
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(x+2)/3x
why?
oh i ssee multiply by reciprical
(x^2 + 5x + 6)/3x = ((x+2)(x+3))/3x so the x+3 would cancel it out
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x^2+5x+6 1 ---------- * --------- 3x (x+3) (x+3)(x+2) 1 ---------- * --------- 3x (x+3) x+2 ---- 3x
\[\frac{x^2+5x+6}{3x} \div (x+3)=\frac{(x+2)(x+3)}{3x} \times \frac{1}{(x+3)}=\frac{x+2}{3x}\]
omg where's the bike, amistre?
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