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Simplify the radical expression 4x^2-7x-2 divided by 8x^3+2x^2+4x+1
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no thats wrong
(4x^2-7x-2)/(8x^3+2x^2+4x+1) ?????????????????????????????
yes thats the problem
it was 2x^2 instead of x^2
degree of denominator is bigger than degree of numerator. what are you supposed to divide? maybe factor and cancel?
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\[4x^2-7x-2 / 8x^3+2x^2+4x+1 \] (4x-8) / (8x^2 + 4) (x - 2) / (2x^2 + 1)
if it is safe to say that is wrong do not say it .. thanks the answer is x-2/(2x^2+1)
corec has it
here is another one 20x+20 divided by 6x+30 times 2x+10 divided by 4x^2-4
denominator is \[(4x+1)(2x^2+1)\] numerator is \[(4x+1)(x-2)\] who gives these problems?
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my math lab
\[\frac{5}{3x-3}\]
everything in site factors.
sight too
clear how to factor them both?
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