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(-10+3i)(2-i)
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-17+16i
hey um what's the radus of the base of a cylinder that has a height of 8cm and a volume of 628cm3 and round your answer to 0.1
price1, if you want to know how to solve it simply foil it out. So you get (-10)(2)+(-10)(-i)+(3i)(2)+(3i)(-i)=-20+10i+6i-3i^2 (i^2=-1) so: -20+16i+3=-17+16i
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